Optimal. Leaf size=624 \[ -\frac {2 A}{a e \sqrt {e x} \left (a+b x^3\right )^{3/2}}-\frac {2 (10 A b-a B) (e x)^{5/2}}{9 a^2 e^4 \left (a+b x^3\right )^{3/2}}-\frac {8 (10 A b-a B) (e x)^{5/2}}{27 a^3 e^4 \sqrt {a+b x^3}}+\frac {8 \left (1+\sqrt {3}\right ) (10 A b-a B) \sqrt {e x} \sqrt {a+b x^3}}{27 a^3 b^{2/3} e^2 \left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )}-\frac {8 (10 A b-a B) \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} E\left (\cos ^{-1}\left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{9\ 3^{3/4} a^{8/3} b^{2/3} e^2 \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {4 \left (1-\sqrt {3}\right ) (10 A b-a B) \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} F\left (\cos ^{-1}\left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{27 \sqrt [4]{3} a^{8/3} b^{2/3} e^2 \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}} \]
[Out]
________________________________________________________________________________________
Rubi [A]
time = 0.49, antiderivative size = 624, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 6, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {464, 296, 335,
314, 231, 1895} \begin {gather*} -\frac {4 \left (1-\sqrt {3}\right ) \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} (10 A b-a B) F\left (\text {ArcCos}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{27 \sqrt [4]{3} a^{8/3} b^{2/3} e^2 \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {8 \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} (10 A b-a B) E\left (\text {ArcCos}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{9\ 3^{3/4} a^{8/3} b^{2/3} e^2 \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}+\frac {8 \left (1+\sqrt {3}\right ) \sqrt {e x} \sqrt {a+b x^3} (10 A b-a B)}{27 a^3 b^{2/3} e^2 \left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )}-\frac {8 (e x)^{5/2} (10 A b-a B)}{27 a^3 e^4 \sqrt {a+b x^3}}-\frac {2 (e x)^{5/2} (10 A b-a B)}{9 a^2 e^4 \left (a+b x^3\right )^{3/2}}-\frac {2 A}{a e \sqrt {e x} \left (a+b x^3\right )^{3/2}} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
Rule 231
Rule 296
Rule 314
Rule 335
Rule 464
Rule 1895
Rubi steps
\begin {align*} \int \frac {A+B x^3}{(e x)^{3/2} \left (a+b x^3\right )^{5/2}} \, dx &=-\frac {2 A}{a e \sqrt {e x} \left (a+b x^3\right )^{3/2}}-\frac {(10 A b-a B) \int \frac {(e x)^{3/2}}{\left (a+b x^3\right )^{5/2}} \, dx}{a e^3}\\ &=-\frac {2 A}{a e \sqrt {e x} \left (a+b x^3\right )^{3/2}}-\frac {2 (10 A b-a B) (e x)^{5/2}}{9 a^2 e^4 \left (a+b x^3\right )^{3/2}}-\frac {(4 (10 A b-a B)) \int \frac {(e x)^{3/2}}{\left (a+b x^3\right )^{3/2}} \, dx}{9 a^2 e^3}\\ &=-\frac {2 A}{a e \sqrt {e x} \left (a+b x^3\right )^{3/2}}-\frac {2 (10 A b-a B) (e x)^{5/2}}{9 a^2 e^4 \left (a+b x^3\right )^{3/2}}-\frac {8 (10 A b-a B) (e x)^{5/2}}{27 a^3 e^4 \sqrt {a+b x^3}}+\frac {(8 (10 A b-a B)) \int \frac {(e x)^{3/2}}{\sqrt {a+b x^3}} \, dx}{27 a^3 e^3}\\ &=-\frac {2 A}{a e \sqrt {e x} \left (a+b x^3\right )^{3/2}}-\frac {2 (10 A b-a B) (e x)^{5/2}}{9 a^2 e^4 \left (a+b x^3\right )^{3/2}}-\frac {8 (10 A b-a B) (e x)^{5/2}}{27 a^3 e^4 \sqrt {a+b x^3}}+\frac {(16 (10 A b-a B)) \text {Subst}\left (\int \frac {x^4}{\sqrt {a+\frac {b x^6}{e^3}}} \, dx,x,\sqrt {e x}\right )}{27 a^3 e^4}\\ &=-\frac {2 A}{a e \sqrt {e x} \left (a+b x^3\right )^{3/2}}-\frac {2 (10 A b-a B) (e x)^{5/2}}{9 a^2 e^4 \left (a+b x^3\right )^{3/2}}-\frac {8 (10 A b-a B) (e x)^{5/2}}{27 a^3 e^4 \sqrt {a+b x^3}}-\frac {(8 (10 A b-a B)) \text {Subst}\left (\int \frac {\left (-1+\sqrt {3}\right ) a^{2/3} e^2-2 b^{2/3} x^4}{\sqrt {a+\frac {b x^6}{e^3}}} \, dx,x,\sqrt {e x}\right )}{27 a^3 b^{2/3} e^4}-\frac {\left (8 \left (1-\sqrt {3}\right ) (10 A b-a B)\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+\frac {b x^6}{e^3}}} \, dx,x,\sqrt {e x}\right )}{27 a^{7/3} b^{2/3} e^2}\\ &=-\frac {2 A}{a e \sqrt {e x} \left (a+b x^3\right )^{3/2}}-\frac {2 (10 A b-a B) (e x)^{5/2}}{9 a^2 e^4 \left (a+b x^3\right )^{3/2}}-\frac {8 (10 A b-a B) (e x)^{5/2}}{27 a^3 e^4 \sqrt {a+b x^3}}+\frac {8 \left (1+\sqrt {3}\right ) (10 A b-a B) \sqrt {e x} \sqrt {a+b x^3}}{27 a^3 b^{2/3} e^2 \left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )}-\frac {8 (10 A b-a B) \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} E\left (\cos ^{-1}\left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{9\ 3^{3/4} a^{8/3} b^{2/3} e^2 \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {4 \left (1-\sqrt {3}\right ) (10 A b-a B) \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} F\left (\cos ^{-1}\left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{27 \sqrt [4]{3} a^{8/3} b^{2/3} e^2 \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}\\ \end {align*}
________________________________________________________________________________________
Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in
optimal.
time = 10.05, size = 85, normalized size = 0.14 \begin {gather*} \frac {2 x \left (-5 a^2 A+(-10 A b+a B) x^3 \left (a+b x^3\right ) \sqrt {1+\frac {b x^3}{a}} \, _2F_1\left (\frac {5}{6},\frac {5}{2};\frac {11}{6};-\frac {b x^3}{a}\right )\right )}{5 a^3 (e x)^{3/2} \left (a+b x^3\right )^{3/2}} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [C] Result contains complex when optimal does not.
time = 0.43, size = 10961, normalized size = 17.57
method | result | size |
elliptic | \(\text {Expression too large to display}\) | \(1225\) |
risch | \(\text {Expression too large to display}\) | \(3336\) |
default | \(\text {Expression too large to display}\) | \(10961\) |
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.50, size = 156, normalized size = 0.25 \begin {gather*} -\frac {2 \, {\left (4 \, {\left ({\left (B a b^{2} - 10 \, A b^{3}\right )} x^{7} + 2 \, {\left (B a^{2} b - 10 \, A a b^{2}\right )} x^{4} + {\left (B a^{3} - 10 \, A a^{2} b\right )} x\right )} \sqrt {a} {\rm weierstrassZeta}\left (0, -\frac {4 \, b}{a}, {\rm weierstrassPInverse}\left (0, -\frac {4 \, b}{a}, \frac {1}{x}\right )\right ) + {\left (4 \, B a^{3} - 13 \, A a^{2} b + {\left (B a^{2} b - 10 \, A a b^{2}\right )} x^{3}\right )} \sqrt {b x^{3} + a} \sqrt {x}\right )} e^{\left (-\frac {3}{2}\right )}}{27 \, {\left (a^{3} b^{3} x^{7} + 2 \, a^{4} b^{2} x^{4} + a^{5} b x\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {B\,x^3+A}{{\left (e\,x\right )}^{3/2}\,{\left (b\,x^3+a\right )}^{5/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________